Question

Question

Hello everyone
The question is we have 3 input x,y,z and the condition we want to fulfill is that i*x+y==z print value of i and if i*x+y!=z print the value of i in which sum i*x+y is nearest to z .

Example like 2 5 11
So i*2+5<=11 print 3

2nd input 4,10,20
So i*4+10<=20
18<=20
Value of i which nearest to z is 2

I solved the 1 input
My code

t=int(input())
for i in range(t):
X,Y,Z=map(int,input().split())
for i in range(0,Z):
if i*X+Y<=Z:
print(i)

I'm stuck in the 2nd input?

Answer 1

Is the lower value always the nearest?

Answer 2

Try this way:

if I*x+y==z : print(I) break
else :
if I*x+y < z : continue
else :
print(i-1) break

#its an algorithm.