why cout work after getch in C++??!!

Question

I want to show a message before an input :

cout<<"Enter a char:";
ch = getche();

but when running program it does not show the message and getche() works and after that the message is showed !!!

Answer 1

Yes, I thought so. This is beyond my expertise, though. This usually rrquires additional libraries (that probably interface via C), non-standard functions, or tapping into the keyboard interrupt.

If it helps, you can try syncing C++ streams with C stdio using
ios::sync_with_stdio(). Maybe this will already do the trick. But getche() is non-standard, so, maybe it won't.

Maybe someone else is able to give an authoritative answer.

Answer 2

Thou shalt not mix C++ streams and C stdio. The weirdest things can happen if those two are unsynchronized.

Answer 3

The whole problem is that, i want to do is :

1- show a message
2- enter ONLY one char
3- do something immediately after entering the char

Answer 4

for example when i pressed "a" it print "apple"
but not with ENTER key
only when i pressed "a" it goes and prints apple

Answer 5

@Ani Jona very thanks for your guide

adding endl solved my problem

cout<<"Enter a char:"<<endl;
ch = getche();

Answer 6

endl will flush the output stream. Happy to hear it is enough to sync :)

Answer 7

I am a little concerned about the "do something immediately". You mean that you want the program to react to a keypress event?