Fibonot checking doesn't work.Why?

Question

Check the cod.Why doesn't the code give any output?

https://code.sololearn.com/cdw079UX5PtS

Answer 1

KAZI FAISAL MAHMUD

1 - you are taking single input but according to example you should take multiple inputs

2 - how this loop will work when n1 = 1 and n2 = 1

for(i = n1 + 1; i < n2; i++) {

Answer 2

KAZI FAISAL MAHMUD OK. Moving forward!
Why will you need to use break in the for loop? You have a known number of iterations.

Answer 3

A͢J Check now.Is it okay?

Answer 4

KAZI FAISAL MAHMUD Before anything else: the Code Playground runner gives errors and warnings. Pls fix them first, then start concerning the calculations.
That said: you declare an array, but only ever use its last item. Why not just declare it as a single int?
Also, the while loop has two exit points - break and while - which are redundant. Moreover, you know the number of iterations beforehand. How about a simpler for loop?
Another hint: practice better code readability. Use consistent indentation and meaningful variable names. This makes it understandable to other people - including who wants to help you.

Answer 5

Emerson Prado Thank you.I will try to obey your advices further.

Anyway, 'Break' is the exit point of forloop.

This problem is to find K'th fibonot(Non-fibonacci number).

Answer 6

Suppose, K=7.Then FN[K]==K[7].
But my loop condition is made with n2.So there is a. Chance to overflow of this array.