Why the output is "Too young"?

Question

Why is it 18 if a comparison is x < 18 and not x <= 18?

Example:

int age = 18;
if (!(age < 18) {
System.out.println("Too young");
}
else {
System.out.println("Welcome");

Thank you all!

Answer 1

Rough code
Int age = 18;
If age==18
Print(exact)
Elif age>18
Print(welcome)
Else
Print(too young)
Try this way you don't get any error in the above code there is redundancy so it show wrong output
Hope it helps 💕💕💞💞

Answer 2

I guess it's because you're using "!" . Your condition is if age is NOT larger than 18 then print out too young .

Answer 3

Kristina Ray

18 < 18 = false

!false = true

So output would be "Too young"

18 <= 18 = true
!true = false

So output would be "Welcome"

Answer 4

See the logical NOT operator before the expression ( age < 18 )? the logical NOT operator inverse the evaluation result. So here ( age < 18 ) is evaluated as true, but the logical NOT operator inverse the result (true) into (false).

P.S. Please add Java in post tags for language context clarity.

Answer 5

The reason is very simple.
First,your condition age<18 is completely false.
But when you use ! Operator the condition becomes true.This is because the compiler only knows the value of age=18.
And that's the reason why you are getting 'Too young' as output.

Answer 6

Remove the sign "!".ok