Can someone explain this code?

Question

#include <stdio.h>

int main() {
unsigned a,b,x,y,temp;
x=a*b;
while(b) temp=a%b,a=b,b=temp;
y=b;
x/=y;
return 0;
}

Answer 1

I don't know where you got this from, but if you try to run this code you'll see warnings about uninitialized variables, which I think triggers the arithmetic error.

FYI, the code execution doesn't make it to the x /= y; line, it is terminated for a critical error ...

Answer 2

<a>, <b>, <x> and <y> are all uninitialized, you may expect them to contain garbage values.

What are you trying to do though?

Answer 3

One reason why x/=y could not be computed is that y must be 0 at the time of execution. y gets the value of b after the while loop which ends if b gets 0. I don't know if that's a good explanation but this should probably be a math error.

Answer 4

I know, I saw the error that compiler reports, so the exam itself has errors. Thank you for clarifying.

Answer 5

This code is for exam, and the correct answer is "there is an error in the last line of code (x/=y)" - but I don't know what's problem in that line of code