can anyone explain?

Question

public class Main
{
public static void main(String[] args)
{
for(int ch='1'; ch<='9'; ch++){

System.out.println(ch);

}
}
}

Answer 1

Sonam
see the Ascii table to understand this

Note: you have declared ch as int 👈 type
👇
for( int ch=1.......) // 👈 here ch is type int

so, when you write ch = '1' 👈 this '1' it will be taken as Ascii value because '1' is a character( 👉 in case of integer datatype ascii value of character is taken because you have initialized int ch with a character not with an integer so the compiler will look for integer data. in case of character, integer data is their ASCII value 👈) so when you print ch you will get the character at Ascii value 1 and so on.

Ascii value 1 represents character 49
Ascii value 2 represents character 50 and so on

Note: 👇👇👇👇👇👇
But when you declared ch as char type 👈👈👈👈

'1' will treated as character constant so you will get

output 👇

1
2
3
4
5
6
7
8
9

https://code.sololearn.com/c1p0RA4Csnq2/?ref=app

Answer 2

this program output: 49
50
51
52
53
54
55
56
57