Can somebody solve this problem using nasted loops in c++ ?it's crashing my mind!

Question

Out put:
1 2 3 4 0
2 4 1 3 0
3 1 4 2 0
0 1 2 3 4

Here's my attempt but it doesn't shows the same out put as i want and i know it could be solved using nasted loops

#include <iostream>
using namespace std;
int main()
{
for(int j=1;j<=4;j++)
{

{
if (j==1)
{

for(int l=1;l<=4;l++)
cout<<l<<"\t";
cout<<"0\n";
}
else
if (j==2)
{
for(int q=1;q<=4;q++)
if (q%2==0)
cout<<q<<"\t";
for(int l=4;l>=1;l--)
if (l%2!=0)
cout<<l<<"\t";
cout<<"0\n";
}

else
if (j==3)
{
for(int q=1;q<=4;q++)
if (q%2!=0)
cout<<q<<"\t";
for(int l=1;l<=4;l++)
if (l%2==0)
cout<<l<<"\t";
cout<<"0\n";
}

if (j==4)
{
cout<<"0\t";
for(int q=1;q<=4;q++)
cout<<q<<"\t";
}

}
}
}

Answer 1

https://code.sololearn.com/c1EIcruZYrWJ/?ref=app

The first three lines follow a given pattern but the last deviate. I did some tweak to get it fixed

Answer 2

Can you specify the input and also show us your attempt

Answer 3

Emma Please link your attempt from Sololearn Playground with your question for needed help.

Answer 4

Your implementation is unnecessarily long.

The output seems to be following a given pattern and requires only two for loops

Answer 5

You're the best!!!!!!! Baribor Saturday

Answer 6

Emma That is a ternary operator

Answer 7

Emma I meant link your code in this way like Baribor Saturday did. That make a help more easier. Happy coding!

Answer 8

What is " (i==4)?1:i " name?
I wanna learn more about it. Baribor Saturday