Can someone help me what this code mean?

Question

It would be best if someone could explain it line by line. Thank you!
--------------------------------------------------------------------------------------
package bu1.ac.kr;

import java.util.Scanner;

public class Minmax {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);
int[] ArrayList = new int[10];

Practice practice = new Practice();

for(int i=0; i<=ArrayList.length;i++) {
ArrayList[i] = input.nextInt();
if(ArrayList[i] == -1) {
break;
}
}

practice.maxValue = practice.max(ArrayList);
practice.minValue = practice.min(ArrayList);

System.out.println();
System.out.println("Max Number : " + practice.maxValue);
System.out.println("Min Number : " + practice.minValue);
}

}

--------------------------------------------------------------------------------------

package bu1.ac.kr;

public class Practice {

int i, j = 0, minValue, maxValue;

public int max(int ArrayList[]) {
maxValue = ArrayList[0];
while(true) {
if(maxValue <= ArrayList[i])
maxValue = ArrayList[i];
if(ArrayList[i] == -1) break;
i++;
}
return maxValue;
}

public int min(int ArrayList[]) {
minValue = ArrayList[0];
while(true) {
if(ArrayList[j] == -1) break;
if(minValue >= ArrayList[j])
minValue = ArrayList[j];
j++;
}
return minValue;
}
}

Answer 1

This code takes array items from user input and outputs its maximum and minimum values.

Answer 2

Minmax class first takes maximum of "10 input values, or until you enter -1". & it uses Practice class which have max method which returns maximum value of array, and min method which return minimum value of array.