Anyone explanation this for loop me.👉for(i=1; i<=n; i++). I'm bigger to the C language. All time i =1? Isn't then?

Question

#include <stdio.h>

int main()

{

    int i, n;

    /* Input upper limit from user */

    printf("Enter any number: ");

    scanf("%d", &n);

    printf("Natural numbers from 1 to %d : \n", n);

    /*

     * Start loop counter from 1 (i=1) and go till n (i<=n)

     * increment the loop count by 1 to get the next value. 

     * For each repetition print the value of i.

     */

    for(i=1; i<=n; i++)

    {

        printf("%d\n", i);

    }

    return 0;

}

Answer 1

Your comment explains the for loop, and your code run shows what it does. Did you notice that i does not remain at 1?
In your case: i=1, since i is less than n , increment i ++ This (++) is the Increment operator - increases integer value by one.
loop repeats until i is equal to n

i = 1 + 1 = 2
i = 2 + 1 = 3
i = 3 + 1 = 4
...
when I = 5 stop

Answer 2

Chris Coder thank you very much sir❤️

Answer 3

Jay Matthews when Enter any number =5
Natural number from 1 to 5
1
2
3
4
5