Possible to do a one liner???

Question

POP SNAP CRACKLE SOLUTION

one = int(input())
two = int(input())
three = int(input())
four = int(input())
five = int(input())
six = int(input())

list = [one, two, three, four, five, six]
final = []
for i in list:
if i%3 == 0:
s = "Pop"
final.append(s)
elif i%2 == 1:
s = "Snap"
final.append(s)
else:
s = "Crackle"
final.append(s)

print(' '.join(final))

Answer 1

print(*[("Pop","Snap","Crackle")[(0,1,2,0,2,1)[int(input())%6]]for _ in"Krispy"])

https://code.sololearn.com/cBl54mZ6XjsX/?ref=app

Answer 2

Yes but you have got a code ugly as hell. I think is better optimize your code:

final =''"
For i in range(6):
val = int(input())
If val%3 == 0:
final = final + "Pop "
Elif val%2 == 0:
final = final + "Snap "
Else:
final = final + "Crackle "

print(final.rstrip())

Answer 3

Rstrip trims final withespaces

Answer 4

Not a one-liner, but easy to understand 😊

in_list = [input(), input(), input(), input(), input(), input()]

result = ""

for x in in_list:
if int(x) % 3 == 0:
result += "Pop "
elif int(x) % 3 != 0 and int(x) % 2 != 0:
result += "Snap "
else:
result += "Crackle "

print(result.rstrip())

Answer 5

David Delgado my specialty lies in web-based coding, and it seems you are more experienced in data science than me, so no arguments here (-:

But to pick a little on your code, I would have done "final += string" instead of "final = final + string" to type less :D

But thanks for the feedback and your code, I adopted your way of taking the input() into the for loop - way better 😊👌 And also the .rstrip() instead of result[:-1]

Answer 6

David Delgado whats rstrip do? never encountered

Thanks for feedback

Answer 7

✩✮★✮✩ crazy cool, if it works,

Why whoudl crackle and snap be in the same position and with consitoon i%2 and how do we know the correct one will be printed ?

Answer 8

✩✮★✮✩ amazing

WhAt _ standss for ?

Answer 9

In my opinion is better don't store variables if you don't need it for the output and save memory reusing the same.

But it's not important in this case because is a little chunk of code.

Answer 10

It's only a way to manage the assignment because of the original C way. I never remember if += works in a language if I'm not in the IDE and try it first ;P

I prefer your way too.

Answer 11

Yeah I get that, and I see that many great coders stick to it either way. I was just picky for the fun of it ;D Buenas tardes amigo (-:

Answer 12

# shorter than ✩✮★✮✩

print(' '.join(['Pop','Crackle','Snap'][i%3]for i in map(int,input().split())))

Answer 13

Ervis Meta - SoloHelper good so far. Now fulfill the requirement to get six inputs.

Answer 14

Just insert how many numbers you want separated by spaces and it'll work no matter that.

Answer 15

Ervis Meta - SoloHelper yep, I like how you made that that work. Unfortunately, the Code Coach inputs come on separate lines.

Edit: I tried it in Code Coach and found that it didn't output the right sequence for Test Case 2: 100 200 300 150 250 350.