sum of all numbers that are a multiple of 3 in the range of 1 to 1000 , by using a loop, please help🙏

Question

Help for understand of answer a question

Answer 1

x = 0
sum = 0
y = 0
while x < 1000:
x = 3 * y
if x < 1000:
sum += y
y += 1
print(sum)

This should work… You do y*3 until y*3 is more than 1000

Answer 2

Wait I used the wrong language xD…

Answer 3

Janne Pls don't give finished code as answer. Prefer giving hints for the OP to find the solution. Let's help others learning.

Answer 4

L... Loop through the range, test if number is multiple of 3, and add it to final sum if it is.
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