Can I use if/and/or in defining a variable?

Question

Code coach exercise for printing child, teen or adult depending on 6 different ages that are input.

age = int(input())

Child = age <11
Teen = age >11 and <18
Adult = age>17

if Child:
print("Child")
elif Teen:
print("Teen")
else:
print("Adult")

Whenever I attempt to use and/ if/ or in the variable teen it always gives syntax error as if it cant be there. However I need teen to consider more than & less than, otherwise a 19y/o is named as a teen.
I have solved with another method bt cn this be done?

Answer 1

age = int(input())

Child = age <11
Teen = age >11 and age<18
Adult = age>17

if Child:
print("Child")
elif Teen:
print("Teen")
else:
print("Adult")
# try this.. your mistake is in 3rd #line .. age> 11 and age <18

Answer 2

Boolean True and False are just 1 and 0 respectively. If child and teen are both False (0), then you get not (0+0) which equals True (1).

Your If Else setup also allows for ODLNT's answer of Teen = age<18 to work as well since you evaluate child first, then Teen then adult.

You also have the option of only checking for two cases and defaulting to the third. If Child = False and Adult = False then Teen = True.

age = int(input())

Child = age<11
Adult = age>17

if Child:
print("Child")
elif Adult:
print("Adult")
else:
print("Teen")

Answer 3

Try either

Teen = age >=11 and age<18
or
Teen = age<18

Answer 4

Interesting. Thanks for explaining it. I learned something today.

Answer 5

child = age < 11

if child:
print('child')

is same like:

if age < 11:
print ('child')
-------------

if a > b:
return True
else:
return False

is like:

return a > b

Answer 6

I like where you were going with that, perhaps you would like this option:

Child = age <11
Adult = age>17
Teen = not (Child+Adult)

The + in that equation is equivalent to an OR in boolean logic.

Answer 7

Because the expression after your ”and” is not correct. age >11 is a correct expression, but < 18 is not. < takes two parameters and you are currently not comparing 18 to anything. You probably meant to write age < 18

Answer 8

Brandon that does look interesting but how do you get it work with the if and print?

Answer 9

Chris Coder Child Teen and Adult already have boolean values (true or false), no need to compare them to anything. The only problem is that Teen has a syntax error

Answer 10

Brandon when working with boolean expressions it’s cleaner in my opinion to work with logical operators directly and not intermediately type juggle to integers.

So you could write
Teen= not ( Child or Adult ).
Also possible would be
Teen = (not Child) and (not Adult)

Answer 11

What language?

Answer 12

Python, sorry.

Answer 13

Thanks John Doe I understood brandons example. I like that this can be done in different ways.
I was just going in this direction.
age = int(input())

if age < 11:
print("child")
elif age <=19 and age >= 11:
print("teen")
else:
print("adult")

Answer 14

Javascript warm message implementation