What is the square of i?

Question

n = int(input())

insects = [n*2**i for i in range(12)]

print(insects)

Answer 1

Oro Collares ,

not quite claer what your question or what your issue is. can you give some more details?

Answer 2

Oro Collares

** has high preference than * so

n*2**i = n*(2**i)

range(12)= [0,1,2,3,4,5,6,7,8,9,10,11]

n => 2

2 * (2**0) = 2 * 1
2 * (2**1) = 2 * 2
2 * (2**2) = 2 * 4

2 * (2**11) = 2 * 2048

Answer 3

PS. ** is not call square, it is raise power to i, or i as exponent.

Answer 4

@Lothar I wanted to know what the square of "**y" was because I thought that for example:

2*2**i i in iteration 3 = 4**3 = 64

but i guess it is:

2*(2**i) i iter 3 = 4*2 = 8