How to create an array of size n filled will 0s.

Question

How can I create an array of size n (user input) filled with 0s?

Answer 1

int arr[size]{};

use brace list initialisation it guarantees to initialize member with 0s

Answer 2

You can't. You need to allocate memory on the heap if you want to do that. You can use std::vector for that (it's basically an array but is allocated on the heap at runtime, and can grow and shrink in size)

```
size_t n;
std::cin >> n;

std::vector<int> arr((n));
```

This will create a dynamic array `arr` of size n, filled with 0s

EDIT: just to clarify, you CAN initialize an array with 0s as described by Prashanth Kumar if the size is known at compile-time. But if you want to initialize the array with a runtime variable, you need to do this.

Answer 3

wait..oops..
did he said its uses input 😅
sry..i thought he asked compile time fixed size array ...

Answer 4

XXX

https://code.sololearn.com/cwDreLyyQl98/?ref=app