Python

Question

Can anyone tell me what is wrong with my code

contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]

name = input()

for x in contacts:
if name in x:
print(str(x[0])
+" is " + str(x[1]))
break
else:
print("Not Found")

Answer 1

Taher Ahmed Taher

break should be inside if condition

Answer 2

Oma Falk ,

both of the suggested codes are not working properly: (exercise 4.2 intermediate phython)

# 1:
if name in contacts: # >>> is not working properly since we have a *list of tuples*. name can never be found.
print(f" {name} is {contacts[name]}")
else:print("not found")

# 2:
for key,value in contacts.items(): # >>> this code assumes that a dictc is used, but it is a *list of tuples*
if name == key:
print(f"{key} is {value}" # >>> missing closing parenthesis

Answer 3

Hi, try the key value pair (dictionary). Break should be inside the if condition, you must indent the break properly. Your if condition is fix or constant, that causes an error too.
Thank you.

Answer 4

Hi. Steve. Okay. Thank you.

Answer 5

Oma Falk ,

what we are talking about is a *code coach exercise* from a python tutorial. and the code of *contacts* is given as default by sololearn. (intermediate python, tuples, 4.2)

so my opinion is: do the exercise with data as they are given.

Answer 6

If name in contacts:
print(f" {name} is {contacts[name]}")
else:print("not found")

Answer 7

Lothar I see!
Well but it should be a dictionary
contacts=dict(contacts) will do it.
The missing parenthesis is fixed.
Thanks for checking😘

Answer 8

Cris Tradio I don't see any problem with the if. If he just indents the break to be under the if, his code should work as expected

Answer 9

for key,value in contacts.items():
If name == key:
print(f"{key} is {value}"