I am not able to detect the error, logic is correct.Help me out with this

Question

contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
name= input()
for x in contacts:
if name in x:
print(str(x[0]) + " is " + str(x[1]))
break
else:
print("Not found")

Answer 1

Kashish Khan ,

here some hints:

> the output 'Not found' is currently printed repeatedly depending on the position of the word in the contacts list.

> this output should be given only once from outside of the for loop

> maybe you need a helpers variable that holds the state if the input word is found inside the loop or not

Answer 2

The logic is not whole correct. Try to solve it yourself. This is better for learning of solution skills.

Answer 3

I don't think the logic is correct try reviewing your code