C++ 1 TO 10 AND REVERSE LOOP

Question

my output should be:
1
2
3
4
5
6
7
8
9
10
9
8
7
6
5
4
3
2
1
0

this is my code the number 9 is disappearing pls helpp
NOTE: dont change int y= 9 because i already tried it since there should be a 0 at the end

https://www.sololearn.com/compiler-playground/c3sLQ7r55Q50

Answer 1

soupie Maybe you could initialize "y" with 9 instead of 8?
(And it looks like you initialized x twice, therefore the warning message.)

Jayakrishna🇮🇳 , Snehil Pandey Thank you!!!

Answer 2

Jayakrishna🇮🇳 How do we need to change the links to make it accessible using the app?

Answer 3

Lisa
in the link, Replace 'www.' with 'code.'
Remove complier-playground/
https://code.sololearn.com/c3sLQ7r55Q50

edit:
soupie
you can try int y = 9; then condition x<=20 instead of x<20

Answer 4

https://code.sololearn.com/cIm4q1sAAxy4/?ref=app
Lisa check this but it's in python
[This is not the answer]

Answer 5

soupie it works if you initialize y = 9, and adjust the end condition of the loop to x<=20 (insert =).

There is also a mathematical solution. The "V" shape of the output is characteristic of the absolute value function. You have to #include the math library to get abs(). This gives the desired output:

#include <iostream>
#include <cmath>
using namespace std;
int main() {
for(int x = -9; x <= 10; x++)
cout << 10-abs(x) << "\n";
return 0;
}

Answer 6

here is my easy and simple approach

https://code.sololearn.com/c3csPk5w8uWo/?ref=app

Answer 7

Brian There are many approaches to solve the question, you can also have:

#include <iostream>
using namespace std;

int main() {
for(int i=1,n=1;i>0;i+=n){
if(i==10) n=-1;
cout<<i<<endl;
}
return 0;
}

But soupie has asked for corrections in his code not for new approach