Code is not running in 9 and 11 line , Error | I couldn't understand plz help

Question

#include <iostream>
using namespace std;

int main() {
int a , b ;
int total marks ;
cin >> a ;
cin >> b ;
cin >> total marks = a+b ;
cout << "a is \n" << a << "\n b is \n" << b << total marks = a+b << endl ;
if ( a+b>= 150) {
cout << "Passed" ;
if (a+b==200) {
cout << "Badass" ;
}
}
else {
cout << "Better luck next time" ;
}
return 0;
}

Answer 1

1)
cin >> total_marks; // remove =a+b

2) Either use before as
total_marks = a+b ;
Or sorround by braces in cout like

cout << "a is \n" << a << "\n b is \n" << b << (total_marks = a+b) ;

edit :
Keshav Karn
if you are taking input into total_marks then
actually why to assign sum of a, b to total_marks...
just use without any assigent statement.

cout << "a is \n" << a << "\n b is \n" << b << "\n" << total_marks;

Answer 2

Thank you sir for helping | Keep helping me in future also plz

Answer 3

int total marks ; invalid ,variables don't includes space or any special characters. Use _ underscore instead.

cin >> total marks = a+b; invalid statement, what are you trying by this? Taking input or assigning sum of a, b?
Hope it helps..

Answer 4

Taking input sir

Answer 5

#include <iostream>
using namespace std;

int main() {
int a , b ;
int total_marks ;
cin >> a ;
cin >> b ;
cin >> total_marks = a+b ;
cout << "a is \n" << a << "\n b is \n" << b << total_marks = a+b ;
if ( a+b>= 150) {
cout << "Passed" ;
if (a+b==200) {
cout << "Badass" ;
}
}
else {
cout << "Better luck next time" ;
}
return 0;
}

Answer 6

Code is not running yet

Answer 7

I will try...
You're welcome..