How can I write a ruby code that takes in an array of integers and return true if any three consecutive elements sum to 7

Question

=begin
THIS ISN'T CORRECT, CAN SOMEONE EXPLAIN IT DEEPLY WHY IT ALWAYS RETURN THE DEFAULT "ELSE" TO ME?
=end

arr = [2,1,5,1,0]
case arr
when ([2 + 1 + 0] == 7)
puts "False"
when ([2 + 1 + 5] == 7)
puts "False"
when ([1 + 5 + 1] == 7)
else
puts "None is added up to 7"
end

Answer 1

I think it's because you're testing a list with the element 7 to be the number 7, like that:
[1 + 5 + 1] = [7] =/= 7

try a for loop:

arr = [2,1,5,1,0]

seven = false

for i in (0..arr.length-3)
if (arr[i] + arr[i+1] + arr[i+2]) == 7
seven = true
end
end
puts seven