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On Dictionary
Pls I tried this code: food={ "Lettuce":5, "Carrot":4, "Mango":10, "Chesseburger":0,} count=0 foods=input() y=foods.split(" ") for i in y: z=food.get(i) count=count+z print(count) >>It didn't work on Solo learn but did on my laptop .it is a practise question Izzy iguana on code coach Thank u
11 Answers
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What does Sololearn say?
Also, you don't need comma in the last dictionary item, since there are no more items afterwards
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It works you just didnt do the check if it greater then some value print something not the sum
reread the problem
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Try this.
snacks = input()
s_snacks = snacks.split()
count = 0
points = {
"Lettuce": 5,
"Carrot": 4,
"Mango": 9,
"Cheeseburger": 0
}
#iterate available snacks
for s_snack in s_snacks:
if s_snack in points:
count += points[s_snack]
if count >= 10:
print("Come on Down!")
else:
print("Time to wait")
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Ion Kare sorry I dont understand wht ur saying
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Oyedeji Hiqmat
"You need 10 total snack points to bring it down. Lettuce is worth 5, Carrot is worth 4, Mango is worth 9, and Cheeseburger is worth 0."
"Task:
Evaluate whether or not you have enough snack points to convince your iguana to come down."
"Output Format:
A string that says 'Come on Down!' if you have enough points, or 'Time to wait' if you do not. "
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Ohh I didnt finish it
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Ion Kare but thanks
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MwaĂŒra thank u very muh
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MwaĂŒra didnt have to change the whole code , he just needed to remove the print(count) with -> if count >= 10 : print("come on down") else: print("time to eat")
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Hello
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Answers