Why print (2 > 4 == 4) False in python. Please kindly explain me.

Answer 1

https://www.sololearn.com/discuss/3191192/?ref=app

It's already answered in your last question.. If you still have doubt, You can continue ask your doubt in the thread, instead of duplicate.

> and == are equal precedence so they evaluated from left to right so first 2 > 4 evaluated it returns false so
False == 4 or 0 == 4 is False.

False means 0 in int value.
Hope it helps...

Answer 2

2>4 gives false which is not equal to 4 so it is giving you False

Answer 3

The expression 2 > 4 == 4 in Python is evaluated as follows:

First, the comparison 2 > 4 is evaluated. This comparison returns False.

Next, the comparison False == 4 is evaluated. This comparison returns False.

So the final result of the expression 2 > 4 == 4 is False, which is why the code print (2 > 4 == 4) outputs False.

It's important to understand the order of operations in such expressions. In this case, the comparison 2 > 4 is evaluated first, and its result (False) is then used in the next comparison False == 4. If the expression had been written as (2 > 4) == 4, it would have raised a SyntaxError, because the comparison 2 > 4 returns a Boolean value of False, which cannot be compared to an integer value of 4.

Answer 4

The expression 2 > 4 == 4 in Python is evaluated as follows:

First, the comparison 2 > 4 is evaluated. This comparison returns False.

Next, the comparison False == 4 is evaluated. This comparison returns False.
Because the boolean value False equals with the number 0(zero) and the comparation == operator compare 0==4. Finally, it returns the boolean value False because 0 is not equal to 4.