Write a program in C++ to print given pattern: **** ### ** #

Question

#include <iostream>
using namespace std;
int main()
{ int rows;
cout << "Enter number of rows: ";
cin >> rows;
for(int i = rows; i >= 1; --i)
{ for(int j = 1; j <= i; ++j)
{ if (j == 1)
System.out.print(i);
else if (i % 2 == 0)
System.out.print('#');
else
System.out.print('*');
}
System.out.println();
}

Answer 1

Yes. Try it and discover that you can do it, too.

If you have trouble solving it, then show what you tried and explain where you are having difficulty.

Answer 2

Simran Samantra
1. You mixed C++ and Java syntax. Use `cout` for printing outputs.

2. Missing } to close main() function body.

3. No need to check <j> == 1, remove that block and make the check for <i> % 2 == 0 becomes the `if` block. Leave the `else` block as is, and use `cout`instead of System.out.print().

Answer 3

Let me see your code, I'll see what I can do to help. Attach link to your code bit inside original post Description above ...