I want explain for this code?

Question

#include <iostream>
using namespace std;

int main() {
for(int i=1;i<=3;++i)
for(int j=1;j<=4;++j)
cout<<i*j<<"\n";
return 0;

Answer 1

// You can understand the code better, when you print out each step of the iteration, for instance like this:

#include <iostream>
using namespace std;

int main() {
for(int i=1;i<=3;++i) {
for(int j=1;j<=4;++j) {
cout << i << "*" << j << "=" << i*j << "\n";
}
}
return 0;
}

Answer 2

Nested loops.
First iteration i=1 and j=1. After it prints i*j, j will be incremented by 1. This will continue until j=4. At this point i will increment by 1 and j will be set to 1 again. This will continue until i=3. At this point the loop will end and main will return 0

Answer 3

1 / i=1 j=1 i*j=1 /
2 / i=1 j=2 i*j=2 /
3 / i=1 j=3 i*j=3 /
4 / i=1 j=4 i*j=4 /now j= 4 loop j<=4 so we add 1 to i
2 / i=2 j=1 i*j=2 /
4 / i=2 j=2 i*j=4 /
6 / i=2 j=3 i*j=6 /
8 / i=2. j=4 i*j=8 /. j= 4 we add 1 to i
3 / i=3 j=1 i*j=3 /
6 / i=3 j=2 i*j=6 /
9 / i=3 j=3 i*j=9 /
12 / i=3 j=4 i*j=12 / j=4 but the loop for i is i<=3 so the execute will end

Answer 4

Thanks👏🏻👍🏻

Answer 5

Salam Tamam Kasm everythinge is perfect you only forget curly bracket ({}) in the for loop:-

Eg. for(int i=1;i<=3;++i){ ←//this thinge({})
for(int j=1;<=4;++j){ ←↑
cout<<i*j<<"\n";
}←
}←
return 0;
}

Answer 6

Alhaaj Raza they aren't strictly necessary if the for statement is a single statement, though it is good style. This will work as written