Is it possible to print all the arguments that passed ?

Question

Like const printAllParam= (a, b, c...) => {
// code
}
printAllParam(1, 5, 6,....)

Answer 1

Yes you can use the destructuring operator '...' for that

function printAllParams(...args){
console.log(args)
}

Answer 2

You can use it with arrow function
and you can also use it to extract properties from objects aswell

example:

let user = {
name : "John",
email : "[e-mail]",
age: 20,
job: "Software Engineer",
address: "Mumbai"
}

// extract name, email, and put all other things in other
let {name,email,...other} = user;

console.log(name,email)
console.log(JSON.stringify(other))

Answer 3

Yes it's possible :

function printAll(...nums) {
for (let num of nums) {
document.write(num)
}
}

printAll(1,2,4,7);
printAll(6,4,9);

Answer 4

Virtual Pixel Thankyou! , it is not possible in arrow function na?

Answer 5

Virtual Pixel okay Got it!
arrow function don't have 𝙖𝙧𝙜𝙪𝙢𝙚𝙣𝙩 object but using spread operator we can achieve it