int main () { int a[3] = {2,7,3}; for (int i=0; i<3; i++){ a[i]-=i; } cout<<a[i]; }

Question

Can someone explain how the answer is 6?

Answer 1

since i's scope is lost it should show error, but since you asked how 6,---
when first iteration is executed, i=0, the first number( a[0] ) 2 is deducted by 0, second iteration second number ( a[1])7 gets deducted by 1(i ), next iteration is not executed as i is greater than 2 now. hence now i=1 only hence prints second number a[1]

Answer 2

This should actually throw an compilation error. The scope of i ends with the for loop and in the next statement, i is not a valid variable.

Answer 3

Showing error😕

Answer 4

That curly brace above cout should come after cout ryt???

Answer 5

The answer is then 261

Answer 6

like it