Why 2 times exception is caught

Question

Hi

Please refer code below:

Why it shows both exception statement as output ? Only exception inside b is not sufficient to handle the throw statement?
https://code.sololearn.com/c844YSckt9AK/?ref=app

Answer 1

function-try-catch:

https://stackoverflow.com/questions/19687146/an-exception-gets-thrown-twice-from-a-constructor-with-a-function-try-block

Answer 2

Because B wss not initialised successfully. You tied it directly to A.
A throws, B throws. All goes to main.
You end up with 2 error messages.

The initialisation did not result in anything useful. It just passed the exception to main.

try this:

https://code.sololearn.com/cKB9fa9cIQ23/?ref=app

Answer 3

Thanks Bob_Li

Answer 4

exception bubbling
https://stackoverflow.com/questions/36571380/do-i-have-to-manually-rethrow-an-exception#36571413

Answer 5

I belive this is different than my usecase.

It says that exception is thrown to next level until it is caught in call hierarchy.

However, I am actually catching it as first place in class B constructor it self.

Had I been having B constructor as follow,

B() : Pa(new A){}

A's exception will not be handled by B class and will be available to main function which created object of B.

My case is having handled exception in B , then why it reaches to main function ?