How can I switch between 2 or more add_child ?

Question

https://sololearn.com/compiler-playground/cn7TS87qF17j/?ref=app

Can this work?

Count = 0
Player = true
Player_2 = false

If count == 0 and player == True:
Add_child 1
Count += 1
Elif count == 1 and player == false and player_2 == true:
Add_child 2
Count -= 1

Answer 1

What is done in a typical tic-tac-toe game with gui is that a cell class is created that initially displays a blank square.
It displays x or o depending on whether the move counter is even or odd. The move counter is incremented when the cell is touched.
Create 9 cells and arrange them into a grid of 3x3 and you have the start of a tic-tac-toe gui.
Then it's a matter of getting the display of the states and determining win/lose/tie.

Here is an html mockup of the basic structure. The internal state representation and win/lose/tie logic is not yet implemented. It's just a quick proof of concept. The important part is that each cel is an individual reactive instance, so there is no need to track the entire board.

https://sololearn.com/compiler-playground/WsvbidfvDLOr/?ref=app

Answer 2

Bob_Li Tóxico ! i have solved, i made 9 series of if who on every serie of if i increment +1 after every player chose, and work. This is the code.

https://sololearn.com/compiler-playground/cOLTg3T2u9GX/?ref=app

Answer 3

Bob_Li i’m a baginner

Answer 4

Nicola
It's a good start.
Getting code to work with the method you know and understand is the way to go. Optimization is an iterative process.🤓

Answer 5

In the provided code, you're attempting to switch between two add_child operations based on certain conditions. However, the code has a few issues. Here's an improved version:

count = 0
player = True
player_2 = False

if count == 0 and player:
print("Adding child 1")
count += 1

elif count == 1 and not player and player_2:
print("Adding child 2")
count -= 1

Answer 6

卂ㄚㄩ丂卄 this the part of cose who i add your if, but continue to add only first 9 add_child and the rest not

Bob_Li check the code

https://sololearn.com/compiler-playground/cn7TS87qF17j/?ref=app

Answer 7

your indentations are messed up...

Answer 8

Bob_Li 卂ㄚㄩ丂卄 Self.croce_1 and self.cerchio_1 are in the same position but after the first self.croce ( add_child ) dont switch to self.cerchio_1 but add self.croce_1

count = 0
player = True
player_2 = False

if count == 0 and player:
self.add_child(self.croce)
count += 1
self.add_child(self.croce_1)
count += 1

if count == 1 and not player and player_2:
self.add_child(self.cerchio_1)

Answer 9

perhaps you want replace child, not add child? But not being familiar with your app, I'm afraid I'm not sure how to do this.

Answer 10

Bob_Li is the tiktaktoe with scene2d PYTHON GUI.
Game with 2 players and 18 simbols, 9 ✖️, and 9 ⭕️, i want to switch between player1 ✖️ and player2 ⭕️.
1 position for both symbols and players

Answer 11

Whit this part of code add first croce and cerchio in te same position,
And croce_1 and cerchio_1 in the other position.
I wanth first croce 1 time in 1 position becouse is the first add, and after i wanth cerchio_1 in the other position, switch between all croce and all cerchio , how to do ?

player = 0
player_1 = 5

for player in range(player_1):
if player_1:
self.add_child(self.croce)
self.add_child(self.croce_1)
if player:
self.add_child(self.cerchio)
self.add_child(self.cerchio_1)

Answer 12

This is the code

https://sololearn.com/compiler-playground/cOLTg3T2u9GX/?ref=app

Answer 13

class MyScene (Scene):
def setup(self):
# ... (código de setup)

def did_change_size(self):
pass

def update(self):
pass

def touch_began(self, touch):
x, y = touch.location

# Lógica para tratar toques e animações

# Loop para adicionar elementos
for _ in range(5): # Utilizando um loop simples para adicionar 5 elementos
self.add_child(self.croce)
self.add_child(self.croce_1)
self.add_child(self.cerchio)
self.add_child(self.cerchio_1)

# Remova esta parte caso você queira adicionar elementos baseado em alguma condição
# player = 0
# player_1 = 5
# for player in range(player_1):
# if player_1:
# self.add_child(self.croce)
# self.add_child(self.croce_1)
# if player:
# self.add_child(self.cerchio)
# self.add_child(self.cerchio_1)

Answer 14

Great. Still too many hardcoded values for my taste, but if it works, then it's good. 9 buttons arranged in a grid might works as well.

Answer 15

Hi