Solved: Code Coach: Jungle Camping. I am stuck. The last result is wrong. Helpful for any advice.

Question

#include <iostream>
#include <vector>
using namespace std;

int main() {
string animal1;
string animal2;
string animal3;
string animal4;
string animal5;
cin >> animal1 >> animal2 >> animal3 >> animal4 >> animal5;
vector<string> sounds{animal1, animal2, animal3, animal4, animal5};
vector<string> animals;

int soundsTotal = sounds.size();
while (soundsTotal > 0) {
for (const string &sound : sounds) {
if (sound == "Rawr") {
animals.push_back("Tiger");
} else if (sound == "Chirp") {
animals.push_back("Bird");
}else if (sound == "Ssss"){
animals.push_back("Snake");
}else if (sound == "Grr"){
animals.push_back("Lion");
}
soundsTotal--; // Decrement soundsTotal within the loop
}
}

for (string animal : animals) {
cout << animal << " ";
}

return 0;
}

Answer 1

12 is also not enough. You should find a way that does not require you to declare a separate variable for each input. You have already used vectors in your code (good idea), so for example:

string input;
vector<string> sounds;
while (cin >> input) {
sounds.push_back(input);
}

Answer 2

How do you know how many sounds you will get? Maybe you should figure out how to handle more than 5.

Answer 3

Tibor Santa Hello, Thanks for helping me. Are you sure that the problem is that my code can only handle 5 inputs? I tried 12 and the last is still wrong. Too bad I cannot see the reason why my code is wrong in the last test result.

Answer 4

Tibor Santa I tried something similar like you did, but I couldn't make it work. But your piece of code looks good and simple. Thanks a lot

Answer 5

Tibor Santa thanks again. It's solved :)

Answer 6

Please, read the description for the task again, because then you will find out that there are only four noises and four animals, and since you are using C++, you could use a map to hold the key/value pairs for the sounds and animals.

Your input will be noises so it would then be easy to pick them from a map what animal it is.