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The difference between the numbers

How can I make the list find values that are less than the first, and then less than the number less than the first, and so on, and then save this difference in the list? Example: 6,4,7,8,5,0 |6|,|4|,7,8,5,|0| Different: 2,4

17th Mar 2024, 9:55 AM
unnamed
unnamed - avatar
9 Answers
+ 1
You can achieve this in Python by iterating through the list and comparing each element with the previous smallest element found so far. Here's a code snippet to do that: def find_differences(lst): differences = [] smallest = lst[0] for i in range(1, len(lst)): if lst[i] < smallest: differences.append(abs(smallest - lst[i])) smallest = lst[i] return differences # Example list lst = [6, 4, 7, 8, 5, 0] # Finding differences result = find_differences(lst) print("Differences:", result) This function iterates through the list starting from the second element. If it finds an element smaller than the smallest one found so far, it calculates the absolute difference and appends it to the differences list. Then it updates the smallest variable. Finally, it returns the differences list.
18th Mar 2024, 3:08 PM
Vivienne Medrano
+ 5
unnamed , without having more detailed samples, we only can guess what the task should achieve exactly. > can you please add the required information?
17th Mar 2024, 8:36 PM
Lothar
Lothar - avatar
+ 4
unnamed from what I can see in your profile, it appears that you are comfortable working with variables, input, print, lists, conditionals, if statements, and loops. That's good, because this task will use all of the above. If an algorithm is too complex to comprehend all at once then take baby steps testing and refining the algorithm. Start with the simple comparison of the first two elements. If they meet the criteron then store the difference in a list. Figure out how to generalize that comparison in a loop for the whole list. Figure out how to initialize and update loop variables to change each time you detect a true comparison. You might consider using nested loops, too. Write code. Test. Refine. Repeat as needed.
17th Mar 2024, 3:49 PM
Brian
Brian - avatar
+ 4
Original List: [6, 4, 7, 8, 5, 0] 1st result list: [4, 5, 0] Different between the first element: 6 - 4 = 2 2nd result list: [0] Different between the first element: 4 - 0 = 4 Agree with Brian's suggestion. You can create temporary variables to hold the work in progress product.
17th Mar 2024, 4:28 PM
Wong Hei Ming
Wong Hei Ming - avatar
+ 3
unnamed And what about the differences of 7-5, 7-0, 8-5 and 8-0?
17th Mar 2024, 8:13 PM
JaScript
JaScript - avatar
+ 2
Why is the result list in the example: 2,4? What is 2 what is 4? Dou you have additional example?
17th Mar 2024, 10:24 AM
JaScript
JaScript - avatar
+ 1
Isn't there a min method for lists, which finds the minimum? Another way is to do a few sorts, iterating through the list, saving the lowest value, locating the next lowest and finding the difference, adding that to a new list etc...
17th Mar 2024, 3:05 PM
Ausgrindtube
Ausgrindtube - avatar
+ 1
unnamed , I don't understand the requirements. Can you give a link to the task description?
17th Mar 2024, 8:15 PM
Rain
Rain - avatar
0
JaScript Its different with values different between 6 and 4 is 2 and between 4 and 0 is 4 as a result, you should get a list [2,4]
17th Mar 2024, 10:36 AM
unnamed
unnamed - avatar