+ 1
Code couch: Halloween candy
I don't know what I'm missing here: houses = int(input()) total_items = houses num_dollar_bills = 2 #your code goes here percentage = (num_dollar_bills / total_items) * 100 rounded_percentage = round(percentage) print(rounded_percentage) I passed the test case 1 and 2 but 3, 4 and 5 don't work they are hidden so I'm not sure what I did wrong
5 Answers
+ 3
houses = int(input())
#your code goes here
a = 2/houses
b = a * 100
c = int(b)
if c == b:
print (c)
else:
print (c + 1)
here you go :) a valid and easier code
+ 6
[sp.: Dode couch = Code Coach]
Jordan it seems that you missed a small detail in the requirements.
Output Format
A percentage value rounded *up* to the nearest whole number.
Your code is only rounding. To round up, use the ceil() function.
+ 4
Jordan you could implement your own ceil function. Here is one way that I tried successfully with Code Coach:
def ceil(a):
return int(a)+(a>int(a))
Although there is a simpler way. Just add 0.5 before rounding:
rounded_percentage = round(percentage + 0.5)
This passes all the tests as well. I should mention, though, that this latter technique is not a general way to make a ceil function. There is an edge case where it may give a different result. That is, if percentage is an odd whole number, then round with added 0.5 would bump it up to the next whole number. The ceil function I gave does it better.
+ 2
Brian thank you
I didn't noticed the "round UP" đ
CODE UPDATE
import math
houses = int(input())
total_items = houses
num_dollar_bills = 2
#your code goes here
percentage = (num_dollar_bills / total_items) * 100
rounded_percentage = math.ceil(percentage)
print(rounded_percentage)
is there a way to do this code without the import?
+ 1
thata đč thank you
Your code is way simpler then mine