Why is this code not working (Why is it showing undeclared all the time)

Question

#include <stdio.h>

int main() {
char value;
printf ("Enter a letter\n");
scanf ("%c", &value);

if (value == a) {
printf ("A");
}
else if (value == b) {
printf ("B");
}
else if (value == c) {
printf ("C");
}
else if (value == d) {
printf ("D");
}
else if (value == e) {
printf ("E");
}
else if (value == f) {
printf ("F");
}
else if (value == g) {
printf ("G");
}
else if (value == h) {
printf ("H");
}
else if (value == i) {
printf ("I");
}
else if (value == j) {
printf ("J");
}
else if (value == k) {
printf ("K");
}
else if (value == l) {
printf ("L");
}
else if (value == m) {
printf ("M");
}
else if (value == n) {
printf ("N");
}
else if (value == o) {
printf ("O");
}
else if (value == p) {
printf ("P");
}
else if (value == q) {
printf ("Q");
}
else if (value == r) {
printf ("R");
}
else if (value == s) {
printf ("S");
}
else if (value == t) {
printf ("T");
}
else if (value == u) {
printf ("U");
}
else if (value == v) {
printf ("V");
}
else if (value == w) {
printf ("W");
}
else if (value == x) {
printf ("X");
}
else if (value == y) {
printf ("Y");
}
else (value == z) {
printf ("Z");
}
return 0;
}

Answer 1

Nishit Mehta in the way that the compiler sees it, variables a, b, c, ..., z are all undefined. I think you intended to compare the input with characters 'a', 'b', 'c', ..., 'z' instead of variables. Make an adjustment to denote single characters with single quotation marks. (Keep the double quotation marks on the scanf() and printf() strings). For example:

if (value == 'a') {
printf("A");
}

Answer 2

char

declare between '' not ""

https://www.learnc.net/c-tutorial/c-character-type/

I hope this helps a bit more :-)

Answer 3

Nishit Mehta ,

Please add a tag for the language.