Problem with class grade analyzer

Question

I typed in the code and made a mistake, so it looks like this:
grades = [8.5, 7.9, 6.8, 8.2, 9, 6.3, 8.4]
count = 0

# Count the number of grades above 8.0
for grade in grades:
print(grades)

# Display the result
for grade in grades:
if grade >= 8.0:
print(grade)

Is there any help on making this code correct?

Answer 1

The output should be the number of elements in the grades list whose value is greater than 8.0.

for grade in grades:
if grade > 8.0:
count+=1

#This part of code will count the number of grades greater than 8.0 and stored in the count variable.

#Now just output the value of count

Answer 2

Tiffany Nguyen ,

here your code with some comments how to fix the issues:

grades = [8.5, 7.9, 6.8, 8.2, 9, 6.3, 8.4]
count = 0

# Count the number of grades *above 8.0*

for grade in grades: # *** this part is not required
print(grades) # *** this part is not required

# Display the result
for grade in grades:
if grade >= 8.0: # *** should be > 8, not >=
count ... # *** counter should be incremented here
print(count) # *** after the loop print counter

btw: it would be helpful if the tutorial name / lesson name / exercise name is mentioned.

Answer 3

# Hi Tiffany Nguyen,

# NumPy is a powerful tool for numerical tasks:

import numpy as np

LIMIT = 8.0
GRADES = (8.5, 7.9, 6.8, 8.2, 9, 6.3, 8.4)

arr_grades = np.array(GRADES)
res = np.sum(arr_grades > LIMIT)

print(
f"For {GRADES}:\n\n"
f"\t-> {res} numbers > {LIMIT}"
)

# https://sololearn.com/compiler-playground/c1rf8styCw4f/?ref=app

Answer 4

grades = [8.5, 7.9, 6.8, 8.2, 9, 6.3, 8.4]
count = 0

for grade in grades:
if grade > 8.0:
count += 1

print(count)

Answer 5

grades = [8.5, 7.9, 6.8, 8.2, 9, 6.3, 8.4]
count = 0

# Count the number of grades above 8.0
for grade in grades:
if grade > 8.0:
count += 1

# Display the result
print(count)