Sums problems

Question

We can easily return twice or thrice times of sum of 2 or 3 number is equal . Such as
def num(x,y):
sum = x+y
if x==y:
sum*=3
return sum
print(num(5,5))

My question is if there are more than 100 or above numbers are equal how can I code the number?

Answer 1

You can use args for this case. Below is an example

def num(*args):
# Get the sum of all numbers
total_sum = sum(args)

# Check if all numbers are the same
if all(x == args[0] for x in args):
total_sum *= 3

return total_sum

# Test with 100 equal numbers
print(num(*([5] * 100))) # Passing a list of 100 numbers, all equal to 5