What is incorrect in this code

Question

players = ["Alice", "Bob", "Charlie", "David", "Eve", "Frank"]

# Create 3 lists with 2 players each
# Use slicing to create a list for Group 1
g1 = players[0:2]

# Use slicing to create a list for Group 2
g2 = players[2:4]

# Use slicing to create a list for Group 3
g3 = players[4:6]

# Display the 1st group
print("Group 1: \n",g1)

# Display the 2nd group
print("Group 2: \n",g2)

# Display the 3rd group
print("Group 3: \n",g3)

Answer 1

Veena Vijay ,

the code seems to be correct since it does not raise any exception. but the output is *not* as expected.

> this is an exercise called `relay race` from the python tutorial `python developer`.

# the output of the current code is:

Group 1:
['Alice', 'Bob']
Group 2:
...

this is *not correct*. the line with the names should start *without a space* at the beginning of the line like:

Group 1:
['Alice', 'Bob']
Group 2:
...

Answer 2

‏‪‏‪‏‪‏‪Crazy Person‬‏‬‏‬‏ ,
the output of your code sample is *not as expected*. read the comments in my post.

> the reason for the (unnecessary) space at the begin of the line with the names is that print inserts a space (by default) when we use a comma to separate multiple arguments.

to get the output done properly, we can set the separator to an empty string like:
print("Group 1:\n", g1, sep='')

Answer 3

why do you say it's incorrect?
It's a good code.

Answer 4

There's nothing wrong with the code from what I've seen
Why are u saying something is incorrect?

Answer 5

the code is functioning as intended and there are no errors.

Answer 6

Lothar
good catch. I didn't realize it was a code exercise problem.

Yeah, those can be strict with spaces, spelling and capitalization.

my more_itertools code also don't work there, it seems like installing modules is restricted, so I deleted it to avoid confusing people...

Answer 7

players = ["Alice", "Bob", "Charlie", "David", "Eve", "Frank"]

# Create 3 lists with 2 players each
# Use slicing to create a list for Group 1
g1 = players[0:2]

# Use slicing to create a list for Group 2
g2 = players[2:4]

# Use slicing to create a list for Group 3
g3 = players[4:6]

# Display the 1st group
print("Group 1:\n", g1)

# Display the 2nd group
print("Group 2:\n", g2)

# Display the 3rd group
print("Group 3:\n", g3)

Answer 8

The output would be like this

Group 1:
['Alice', 'Bob']
Group 2:
['Charlie', 'David']
Group 3:
['Eve', 'Frank']

Answer 9

Hi Veena,

if you don't want a space before the group, you can do like this:

# Display the 1st group
print(f"Group 1:\n{g1}")

# Display the 2nd group
print(f"Group 2:\n{g2}")

# Display the 3rd group
print(f"Group 3:\n{g3}")

Answer 10

So looks like there was an issue in the tool itself.Thank you all and confirming that my code was correct.