#include <iostream> using namespace std; int main() { int i=2; i=i++; cout<<"Result : " <<i++ + i++; return 0;}

Question

#include <stdio.h>
#include<conio.h>

int main() {
int i=2;
i=i++;
printf("Result : %d" ,i++ + i++);
return 0;
}

output will be same or not ?
if your answer​ yes or no, so tell me why ???

Answer 1

I think that the output will be the same. std::cout works like printf, but it doesnt have the same formatting capabilities.

P.S. You don't have to write i=i++, just i++ will do the same.

Answer 2

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