What the answer

Question

Fill in the blanks to print "Yes" if the list contains 'z':

what's the answer
letters = ['a', 'b', 'z']

_ "z" _

letters:
print("Yes")

Answer 1

list.append ('z')
print( len (list) )

Answer 2

the ans is

if "z" in letters:
print("Yes")

Answer 3

Fill in the blanks to create a set, add the letter "z" to it, and print its length.

nums =

{

"a", "b", "c", "d"

}

nums.

add

("z")
print(

len

(nums))

Answer 4

If"z"in

Answer 5

Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42.
Stack<int> st = new Stack<
int
>();

st
.Push(11);

st.Push(42);

st.Push(15);

(st.Contains(42)) {

Console.WriteLine("yes");

}

What is the answer?

Answer 6

Stack<int> st = new Stack<
int
>();

st
.Push(11);

st.Push(42);

st.Push(15);

if(st.Contains(42)) {

Console.WriteLine("yes");

}

Answer 7

Thanks to Makhan

Answer 8

la respuesta es if y en el otro recuadro va in

Answer 9

1. if
2. in

Answer 10

Drag and drop from the options below to add 'z' to the end of the list and print the list's length.
list. ('z')
print( ) )
insert len append (list) index.
What go in the gap

Answer 11

list.append ('z')
print( len (list) )

Answer 12

void print(int n) {
if (n < 0) return;
printf("%d", n);
print(n - 1);
}

Answer 13

Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z']

"Зет"

буквы:
печать ("да")

Answer 14

letters = ['a', 'b', 'z']
if "z" in letters:
print("Yes")

Answer 15

letters = ['a', 'b', 'c']

for

l

in

letters

:

print(l)

Answer 16

can you please try the following

letters = ['a', 'b', 'z']

if

"z"

in

letters:
print("Yes")

Answer 17

The answer is
if "z" in letters:

Answer 18

Fill in the blanks to create a set, add the letter "z" to it, and print its length.

nums =

{

"a", "b", "c", "d"

}

nums.

add

("z")
print(

len

(nums))

Answer 19

: )