Str.startswith ()

Question

beg end index ??
can someone explain it for me?
I don't understand why it's false.
https://code.sololearn.com/c6M1SE86lj04/?ref=app

Answer 1

in your example string the indexes are as follows

0123456789.....
t,h,i,s,i,s, ,a, ,s,t,r,i,n,g

as you can see, index 4 have the letter 'i'

Answer 2

beg and end are optional parameters
the default is start at 0

passing beg and end parameters will override default, and will consider the beg index as the begining

Answer 3

https://www.tutorialspoint.com/JUMP_LINK__&&__python__&&__JUMP_LINK/string_startswith.htm

from the link:

str = "this is string example....wow!!!";
print str.startswith( 'this' ) # True
print str.startswith( 'is', 2, 4 ) # True
print str.startswith( 'this', 2, 4 ) # False

beg/eng is used to set start index and end index for the matched string

Answer 4

your code:

str='this is a string'
print (str.startswith('a', 4,6))

letter at index is ' ' (space), that's why False is returned

this code however will return True

str='thisais a string'
print (str.startswith('a', 4,6))

Answer 5

maybe this will help

https://code.sololearn.com/ciQfFJ3ddk93/?ref=app

Answer 6

no probs :)

Answer 7

Ah I see it now.. from the example 'this is string example...' I thought that 'is' was for the verb lol
(so it's like they chose the second word but no..)
thank you !

Answer 8

Actually I writed this post because of this website because when I tried:
print str.startswirh( 'string', 4, 6)
I got False..and I don't understand why .

Answer 9

It returns False.
and don't we start by 0 ?

Answer 10

thanks ..I understand how it works I just don't understand why it's not working in my example :)

Answer 11

beg and end are optional parameters
the default is start at 0

passing beg and end parameters will override default, and will consider the beg index as the begining
but in all cases the index of 'a' is 4..right?