Pls explain me this code..

Question

#include <iostream>
using namespace std;

int main() {
int c,j=0,n=0;
for (c=1;c<=5;c++)
{
j=j++;
}
n=j+2;
j=n;
cout<<j;
return 0;
}

Answer 1

I was confused. But then I realize it's j++ not ++j

Answer 2

Everytime j=j++ gives the same value to j it means j=0 in every loop . After loop it is added by 2. Thus u get j=2. This is one quiz question.

Answer 3

Good question. Now,here if we could use the keyword "static" to declare j, then may be, as per definition, it would update "j" everytime the for loop revolve.

Answer 4

Thanku @mattias Ericsson now I understood

Answer 5

no the output is 2

Answer 6

that's why am confused

Answer 7

the key is to study j=j++;

Answer 8

no the answer is 2.. @vishnu ks

Answer 9

K @vishnu

Answer 10

yeah sure

Answer 11

done Vishnu

Answer 12

Ya @vignesh The output is 2. I got it.

Answer 13

so easy 2