letter={'s', 'a', 'i', 'j', 'o', 'n'} print(letters.remove('i')) showing error. How to write it exact way? And explainto reverse

Answer 1

try to replace curses brackets by squares brackets (list)

use curses brackets to define a dictionary with key: value

Answer 2

There is a misspelling in your code. You declared 'letter' set and you try to run a method on 'letters'.
It should go like this:
letters={'s', 'a', 'i', 'j', 'o', 'n'}
letters.remove('i')
print(letters)

reverse() can't be applied on sets, as they are variables of an unordered type.

Answer 3

This is a set. As a type, it is unordered and can carry unique values only. When printed though, it usually is displayed in an ordered fashion. But that is not its intrinsic trait - it is probably somehow knit into __repr__ or __str__ method which are used by print().

Try to create a set of unique values of different types. You'll see that it is 'out of order' ;)

Answer 4

Kuba.. This lead me to a question.. Why does this

letter={'s', 'a', 'i', 'j', 'o', 'n'}
print(letter)

give the following output?

{'a', 'i', 'j', 'o', 'n', 's'}

Why move the first element to the end?

Answer 5

I see.. changing a few elements to ints piled the ints together.. So out of order, in a somewhat orderly fashion.. Interesting...