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What is the diffrence between "int k=2; " and "int k{2};"
why do we need to declare the value in " {}" ??
1 Answer
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Initializing with braces is called List initialization, which was introduced in C++ in 2011. Which means it doesn't allow narrowing, I'm gonna copy/paste from the Author's book itself:
⢠An integer cannot be converted to another integer that cannot hold its value. For example, char to int is allowed, but not int to char.
⢠A floating-point value cannot be converted to another floating-point type that cannot hold its value. For example, float to double is allowed, but not double to float.
⢠A floating-point value cannot be converted to an integer type.
⢠An integer value cannot be converted to a floating-point type.
The only situation where = is preferred over {} is when using auto keyword to get the type determined by the initializer. It takes time to kick in.
Research more on Stackoverflow, people have amazing and more thorough answers.