why this output? int x=3; x=++x + ++x + ++x; cout<<x; //output==16 ?

Answer 1

there is a rule that expalin that a variable can not be upadated twice in an expression. if such things happen the result depends upon the implementation of that specific compiler .

Answer 2

something wrong!

Answer 3

so we can't forecast result in the same examples?

Answer 4

OK this output depends on compiler

Answer 5

yeh something wrong its ouput should be 15

Answer 6

it should be 18