What are the differences between ++i and i++ as incrementors of a for loop?

Answer 1

--x decrements the value first and uses the new value in the statement.
x-- first executes the statement and decrements the value of x after that.

exampeles:

int x=1;
cout<<++x;//output is 2.

int y=1;
cout<<y++;//output is 1

but be careful in this example:

int x=1;
int y=3;

cout<<++x+y--+x;

the output will be 7.
why ?
first x changed to 2 .++x

second y will be same because we took the value of y before the decrement .y--

third : the second x will be 2 because it increased at first

so the answer is 2+3+2=7

Answer 2

you can test that by using codes

https://code.sololearn.com/cmcM0rNvTl84/?ref=app

Answer 3

https://www.sololearn.com/discuss/489143/?ref=app

Answer 4

--decrements
Assigns than decreaments--

Answer 5

The ++i increments i before the operation while the i++ increments i after the operation.

Write and run a simple for loop with cout << i to compare the two.

Answer 6

++i is pre-increment, which means first increment then use it by 1.

i++ is pre-increment, which means first use then increment.

To understand it better, try to do a simple practical.

Answer 7

So, I found these two links:
https://www.quora.com/Do-you-use-i++-or-++i-in-a-for-loop-And-why?share=1 – General discussion of the question
https://stackoverflow.com/questions/484462/difference-between-i-and-i-in-a-loop/484492#484492 – Explanation

tl;dr: if i is something simple and not an iterator, it doesn't matter if you use ++i or i++ as increment in a for loop. But because it could be an iterator where operator++ is overloaded, it might be better to stick to ++i.

Answer 8

I can't get it can anyone describe ezly pls?