someone should tell me how it works, with full description 😷

Question

int x = 4
int y = 3
cout << ++x*y-- ;

output: 15

Answer 1

first will execute ++x --> x = 5
second will execute x*y --> 5*3 = 15
third will print the result "15"
forth will ecexute y-- --> y = 2

Answer 2

this is the order in which it all happens:
1) ++x increments x from 4 to 5
2) x*y -> 5*3 = 15
3) y-- decrease y to 2 (the calculation in 2 has already been made so that is the final output)
4) if you were to check the value of y you'd see it is now 2

Answer 3

thanks guys helpful for me too...

Answer 4

it works after the execution of the expression.
ex:
int x = 4;
int y = 3;
cout << ++x*y--; // will output 15

cout << y;
// now value of y change and will output 2

Answer 5

with prefix ++x will increment x by 1 then execute the expression, while in postfix y-- will execute the expression then decrement the value of y by 1.

Answer 6

int x = 5;
int y = 3;
cout << ++x*y--;

it shows 18 not 15

but if you mean

cout << x++ * y--;

it will shows 15

Answer 7

you'r welcome..

Answer 8

you'r welcome..😊

Answer 9

you mean there is no work for '--'?

Answer 10

all right but what's about that?

int x = 5
int y = 3
cout << ++x*y--;

it also shows 15?

Answer 11

yup, clear😊 thanks Dakdouk👌

Answer 12

int x = 5;
int y = 3;
cout << ++x*y--;

it shows 18 not 15//can you please explain why is it 18... does it mean only value of x was incremented

but if you mean

cout << x++ * y--;// and here why is it 15

it will shows 15