? and : in c++

Question

int x = 0;
for (int i = 0; i < 4; i++)
{
x += (i % 2 ? 1 : 0);
}

The solution is 2, but how do I do the calculation on paper?

Answer 1

x += (i % 2 ? 1 : 0);

is the same as

if(i % 2) ++x;

or

x += i % 2

--
It just counts the even numbers until a certain number.
I hope this helps

Answer 2

it is ternary operator.
u must be aware of operator precedence and associativity.
which will helpful to perform such statements.
based on that these statements got executed.

Answer 3

It does, thanks!