I dont understand default arguments

Answer 1

Example of default arguments for a function:

int sum(int a = 5, int b = 10)
{
return a + b;
}

int main()
{
cout << sum();
}

Even though we didn't pass any values when we called the function, we still get an output of 15, because a and b have a default value, declared by the = in the function parameters.

If you did want to replace one of these values, you can easily do that by calling the function, and passing values in:

sum(15);

This will call the function, and set a to 15, and b is still 10 from its default value, because we didn't pass a second value in.

Answer 2

i think argument is number whe give to function