Arrays in c++

Question

hey everyone! i want to obtain multiplication with multi-dimensional arrays but i dont know the problem. my output is "1" with my code. can anybody help!
#include<iostream>
using namespace std;
int main() {
int a[10][10];
int j=1, i=1;
while (j < 10) {
a[i][j] = i * j;
if (i <= 10)
i++;
else {
j++;
i = 1; } }
i=1, j=1;
while (i <= 10) {
if(j <= 10) {
cout << a[i][j] << "\t";
j++; }
else {
cout << "\n";
j=1;
i++;
}
return 0;
} }

Answer 1

Your code is below.

What I don't understand is why you need Array.

https://code.sololearn.com/cHr4P2xH7fRN/?ref=app

Answer 2

What do you want to happen?

Answer 3

In the else loop, you set i=1; again, that's not needed. Then after the entire while loop you set both i and j to 1. (i=1, j=1) So whatever i and j were being set to in the loop, they are 1 again after. And 1*1=1, so your output is 1.

Answer 4

Can you make the code public and share the link? That way it's easier to check

Answer 5

I actually meant a link tothe Playground like this, but this worked too. I changed up some things. Removed the line i+1, j=1; after your while loop. Just look at your and my code for all the differences. It now returns the product of the last incremented i and j

https://code.sololearn.com/cLvEwJR25wd3/?ref=app

Answer 6

thanks bro thats what i wanted
i use array just for better understanding and practice

Answer 7

i have edited my code a little but still output is 1 can you edit my code and write the right answer please!

Answer 8

https://justpaste.it/17lmq

Answer 9

bro this code is wrong too! the output is 100 in your code.

Answer 10

iwant to optain multiplication in output
like this:
01 02 03 04 05 06 07 08 09
02 04 06 08 10 12 14 16 18
03 06 09 12 15 18 21 24 27
04 08 12 16 20 24 28 32 36
05 10 15 20 25 30 35 40 45
06 12 18 24 30 36 42 48 54
07 14 21 28 35 42 49 56 63
08 16 24 32 40 48 56 64 72
09 18 27 36 45 54 63 72 81

Answer 11

i have edited my cod to this but the output is now "segmentation fault"

#include<iostream>
using namespace std;
int main() {
int a[10][10];
int j=1, i=1;
while (j < 10 || i < 10) {
a[i][j] = i * j;
while (j <= 10) {
j++; }
while (j > 10) {
i++;
j = 1; } }
i=1, j=1;
while (j <= 10 || i <= 10) {
while (j <= 10) {
if (a[i][j] < 10)
cout << "0" << a[i][j] << "\t";
else if (a[i][j] >= 10)
cout << a[i][j] << "\t"; }
while (j > 10) {
cout << "\n";
j=1;
i++; } }
return 0;
}

Answer 12

can you upvote me?

Answer 13

yep