Why does the switch statement automatically execute any code that isn't preceded by a break?

Question

Shouldn't it check if the conditions match first? For example int x = 10 switch(x) case 10 print Hi case 20 print Bye

This prints Hi Bye even if the second case isn't met.

Answer 1

yes, until x is 20!

Answer 2

Ok, thanks for your answers.

Answer 3

Sorry but this aint switch statement
In a situation when a case ( say case 1 )is found , the corresponding statements of case 1are executed
if a break is encountered overthere in case 1 block , the control immediately passes
on to the line of code after the whole block of switch statement without going thru other cases
if a break isnt encountered , the control passes to next case clause
here only if case ( case 2 ) matches , the statements of case 2 are executed otherwise not
and the process goes on until a break statement or the end of switch block is encountered

Answer 4

No, it will not print bye until x is 10. Check your code!

Answer 5

You mean 20? I will check again.

Answer 6

The code playground executed any statement after matching the first one if there wasn't a break. For example day = 1 switch (day) case 1 print Monday case 2 print Tuesday break; case 3 Wednesday prints out Monday Tuesday (the code is written in shorthand of course).

Answer 7

Well, then I fear there must be a problem because switch doesn't work that way. break is used to save execution time for checking every case if the condition is already met. Try running your code in PC!!

Answer 8

hi