why output is not 2?

Question

#include <iostream>
using namespace std;

class a{
public :
virtual void f(){

cout <<1;}
};
class b:public a{
public :
void f(){cout <<2;}
};
class c:public b{
public :
void f(){cout <<3;}
};

int main() {
b *p = new c;
p->f();
return 0;
}

Answer 1

You know what ? You've asked a very good question...
I've told you something wrong :
p->f(); isn't like c.f();
When you create a new c from a b pointer, if two methods are in both class, the one of the base class is called unless it's a virtual function.

Quite difficult... ask if you still have questions

Answer 2

Ook.. thank you very much

Answer 3

I thank you, thanks to you I know I have to work on Inheritance and Ploymorphism...

Answer 4

c inherits from b.

b *p=new c; // pointer on an object c.
p is the pointer. *p is the 'value' of the object pointed (c) so *p->f(); is like c.f();
Ask if you don't understand

Answer 5

Let us ignore the virtual keyword. Now consider -
int main() {
a *p = new b;
p->f(); /*equivalent to b.f()
but output is 1... so according to this o/p of code given in ques should be 2..*/

Answer 6

Then answer should be 2 only as b is the base class for c. Why 3?

Answer 7

It's because of the virtual function of a.
b inherits of a's virtual function...
so b's f() become virtual