Why is the output in 5th line =0 instead of (-10)?

Question

int main() {
int a[]={1,2,3,4,5};
for(int i =0;i<=4;i++){
a[4]=a[4]-a[i];
cout <<a[4]<<endl;
}
cout <<"\n\n\n"<<a[4]%a[1];
return 0;
}// Outputs 4 2 -1 -5 0 0

Answer 1

---------------------
ITERATION: 0:
PROBLEM: (5) - (1)
RESULT: 4
---------------------
ITERATION: 1:
PROBLEM: (4) - (2)
RESULT: 2
---------------------
ITERATION: 2:
PROBLEM: (2) - (3)
RESULT: -1
---------------------
ITERATION: 3:
PROBLEM: (-1) - (4)
RESULT: -5
---------------------
ITERATION: 4:
PROBLEM: (-5) - (-5)
RESULT: 0

https://code.sololearn.com/cr8tPjk10PrX/#cpp

Answer 2

@Soman He is talking about the last iteration of the loop, not the modulo stuff after the loop. It's 0 instead of -10 because -5 - (-5) is 0 since the negative signs cancel each other out.

Answer 3

% returns you reminder from division. Use / operator.