HELP def print_double(x): print(2*x) print_double(3) result??

Answer 1

What is the result of this code?
def print_double(x):
print(2 * x)

print_double(3)

ans: 6

Answer 2

ouu 6. thanks

Answer 3

6

Answer 4

def print_double(x):
print(2*x)
print_double(3)

Answer 5

Not to difficult. Just exchange everywhere inside the function the x by 3. then you just have to calculate.

Answer 6

What is the result of this code?
def print_double(x):
print(2 * x)

print_double(3)

Ans: 6

Answer 7

the ans is 7

Answer 8

yeah its 6

Answer 9

ans :6

Answer 10

You have just defined print_double as 2*x. But in order for it to work you need to put a variable in, you cant double the letter "X". So in the parentheses next to the def function you put in a letter x, that's telling python that the variable is x so when you put (2*x) you're essentially telling python to print 2*a number that you put in. So now everytime you put print_double(#enter number) the variable in the parentheses is going to follow the rule that you just defined, which would be printing it*2.

So if you were to just put:
def print_double(x):
print(x)
Anything you put in the parentheses for print_double() is going to follow the rule you just put down, so in this case all its doing is just printing it. So if I put print_double('hello world") it would just print hello world because that's the rule that I set it as.

Answer 11

indentation

Answer 12

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